展开 ((8x-3)^2)/(64)

解答

展开

\frac{( 8 x - 3 ) ^{2}}{64}

x^{2} - \frac{3 x}{4} + \frac{9}{64}

求解步骤

\frac{( 8 x - 3 ) ^{2}}{64}

(8 x - 3)^{2} = 64 x^{2} - 48 x + 9

= \frac{64 x ^{2} - 48 x + 9}{64}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{64 x ^{2} - 48 x + 9}{64} = \frac{64 x ^{2}}{64} - \frac{48 x}{64} + \frac{9}{64}

= \frac{64 x ^{2}}{64} - \frac{48 x}{64} + \frac{9}{64}

数字相除:

\frac{64}{64} = 1

= x^{2} - \frac{48 x}{64} + \frac{9}{64}

消掉

\frac{48 x}{64} : \frac{3 x}{4}

= x^{2} - \frac{3 x}{4} + \frac{9}{64}

e x p an d \frac{3 ( 2 - x )}{x}

e x p an d 8 x y (3 x - y = 2 z)

e x p an d \frac{( s ^{2} + 2 s + 3 )}{( s + 1 ) ^{3}}

e x p an d (x^{2} + y) d x - x d y

e x p an d (- 2 x^{2} ln (x) + x^{2}) x