展开 e^{t-2}cos((a+b+c)t)

解答

展开

e^{t - 2} cos ((a + b + c) t)

e^{t - 2} cos (a t + t b + c t)

求解步骤

e^{t - 2} cos ((a + b + c) t)

乘开

(a + b + c) t : a t + t b + c t

= e^{t - 2} cos (a t + t b + c t)

e x p an d (a + d t - c)^{2}

e x p an d \frac{4 ( x + y ) ^{2}}{3}

e x p an d 3 + (8 + 4)

e x p an d \frac{s + 5}{( s + 1 ) ( s - 3 )}

e x p an d \frac{n ( n + 1 ) ( n + 2 )}{2}