erweitern ((1+2x^3)^2)/7

Lösung

erweitern

\frac{( 1 + 2 x ^{3} ) ^{2}}{7}

\frac{4 x ^{6}}{7} + \frac{4 x ^{3}}{7} + \frac{1}{7}

Schritte zur Lösung

\frac{( 1 + 2 x ^{3} ) ^{2}}{7}

(1 + 2 x^{3})^{2} = 1 + 4 x^{3} + 4 x^{6}

= \frac{1 + 4 x ^{3} + 4 x ^{6}}{7}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 + 4 x ^{3} + 4 x ^{6}}{7} = \frac{1}{7} + \frac{4 x ^{3}}{7} + \frac{4 x ^{6}}{7}

= \frac{1}{7} + \frac{4 x ^{3}}{7} + \frac{4 x ^{6}}{7}

Rewrite in standard form

= \frac{4 x ^{6}}{7} + \frac{4 x ^{3}}{7} + \frac{1}{7}

e x p an d \frac{( x - 2 ) ^{2}}{x ^{5}}

e x p an d \frac{1}{x ( m - x )}

e x p an d \frac{( x + 1 ) ^{2}}{( x ^{2} + 1 )}

e x p an d \frac{3 s + 5}{( s + 1 ) ^{2} ( s + 2 )}

e x p an d \frac{x + y}{( x + y ) ^{2} + 1}