faktorisieren 6a^2+(9a+1)

Lösung

faktorisieren

6 a^{2} + (9 a + 1)

6 (a - \frac{- 9 + 57}{12}) (a - \frac{- 9 - 57}{12})

Schritte zur Lösung

6 a^{2} + (9 a + 1)

Entferne die Klammern:

(a) = a

= 6 a^{2} + 9 a + 1

Schreibe um

= 6 (a^{2} + \frac{3 a}{2} + \frac{1}{6})

Faktorisiere

a^{2} + \frac{3 a}{2} + \frac{1}{6} : (a - \frac{19 - 3 3}{4 3}) (a - \frac{- 3 3 - 19}{4 3})

6 (a - \frac{19 - 3 3}{4 3}) (a - \frac{- 3 3 - 19}{4 3})

\frac{- 3 3 + 19}{4 3} = \frac{- 9 + 57}{12}

= 6 (a - \frac{57 - 9}{12}) (a - \frac{- 3 3 - 19}{4 3})

\frac{- 3 3 - 19}{4 3} = \frac{- 9 - 57}{12}

= 6 (a - \frac{57 - 9}{12}) (a - \frac{- 9 - 57}{12})

f a c t or ln (x) (e^{s e c^{2} (7 x)})

f a c t or 2 π r + 2 π

f a c t or x^{2} (- cos (ln (x)))

f a c t or 100 f^{2} - 180 ff + 81

f a c t or 3 m m^{2} - 6 mn + 4 m - 8 n