faktorisieren cos^6(A)+sin^6(A)

Lösung

faktorisieren

cos^{6} (A) + sin^{6} (A)

(cos^{2} (A) + sin^{2} (A)) (cos^{4} (A) - cos^{2} (A) sin^{2} (A) + sin^{4} (A))

Schritte zur Lösung

cos^{6} (A) + sin^{6} (A)

Schreibe

cos^{6} (A) + sin^{6} (A)

um:

(cos^{2} (A))^{3} + (sin^{2} (A))^{3}

= (cos^{2} (A))^{3} + (sin^{2} (A))^{3}

Wende Formel zur Summe von dritten Potenzen an:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(cos^{2} (A))^{3} + (sin^{2} (A))^{3} = (cos^{2} (A) + sin^{2} (A)) (cos^{4} (A) - cos^{2} (A) sin^{2} (A) + sin^{4} (A))

= (cos^{2} (A) + sin^{2} (A)) (cos^{4} (A) - cos^{2} (A) sin^{2} (A) + sin^{4} (A))

f a c t or \frac{5 x ^{3} - 135}{x - 3}

f a c t or a c + 5 a + b c + 5 b

f a c t or 25 x^{2} - 5 (5 x) - 89

f a c t or x^{2 + 2 x - 4}

f a c t or 3 am + 2 bm - 6 an - 4 bn