faktorisieren (x+3)^2(x+4)+(x-1)x

Lösung

faktorisieren

(x + 3)^{2} (x + 4) + (x - 1) x

x^{3} + 11 x^{2} + 32 x + 36

Schritte zur Lösung

(x + 3)^{2} (x + 4) + (x - 1) x

= (x + 3)^{2} (x + 4) + x (x - 1)

(x + 3)^{2} : x^{2} + 6 x + 9

= (x^{2} + 6 x + 9) (x + 4) + (x - 1) x

Multipliziere aus

(x^{2} + 6 x + 9) (x + 4) : x^{3} + 10 x^{2} + 33 x + 36

= x^{3} + 10 x^{2} + 33 x + 36 + (x - 1) x

Multipliziere aus

x (x - 1) : x^{2} - x

= x^{3} + 10 x^{2} + 33 x + 36 + x^{2} - x

Vereinfache

x^{3} + 10 x^{2} + 33 x + 36 + x^{2} - x : x^{3} + 11 x^{2} + 32 x + 36

= x^{3} + 11 x^{2} + 32 x + 36

f a c t or 112

f a c t or 10 c h - 35 c h

f a c t or 3 a + 3 b + a v + b v

f a c t or (x + y)^{2} - (x + y) - 2

f a c t or π d^{2} + π^{10} d^{2} \cdot 2