What is factor y^{10}+7y^5-8 ?

The solution to factor y^{10}+7y^5-8 is (y-1)(y^4+y^3+y^2+y+1)(y^5+8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor y^{10}+7y^5-8

factor

y^{10} + 7 y^{5} - 8

(y - 1) (y^{4} + y^{3} + y^{2} + y + 1) (y^{5} + 8)

Solution steps

y^{10} + 7 y^{5} - 8

Use the rational root theorem

= (y - 1) \frac{y ^{10} + 7 y ^{5} - 8}{y - 1}

\frac{y ^{10} + 7 y ^{5} - 8}{y - 1} = y^{9} + y^{8} + y^{7} + y^{6} + y^{5} + 8 y^{4} + 8 y^{3} + 8 y^{2} + 8 y + 8

= (y - 1) (y^{9} + y^{8} + y^{7} + y^{6} + y^{5} + 8 y^{4} + 8 y^{3} + 8 y^{2} + 8 y + 8)

Factor

y^{9} + y^{8} + y^{7} + y^{6} + y^{5} + 8 y^{4} + 8 y^{3} + 8 y^{2} + 8 y + 8 : (y^{4} + y^{3} + y^{2} + y + 1) (y^{5} + 8)

= (y - 1) (y^{4} + y^{3} + y^{2} + y + 1) (y^{5} + 8)

f (x y)

(x - 1)^{3} + 1

(x - 5) (x - 5)

x^{2} + x y + z x + zy

(5 x^{2}) + (7 x - 9)

What is factor y^{10}+7y^5-8 ?
The solution to factor y^{10}+7y^5-8 is (y-1)(y^4+y^3+y^2+y+1)(y^5+8)