faktorisieren y^{10}+7y^5-8

Lösung

faktorisieren

y^{10} + 7 y^{5} - 8

(y - 1) (y^{4} + y^{3} + y^{2} + y + 1) (y^{5} + 8)

Schritte zur Lösung

y^{10} + 7 y^{5} - 8

Wende den rationalen Nullstellentest an

= (y - 1) \frac{y ^{10} + 7 y ^{5} - 8}{y - 1}

\frac{y ^{10} + 7 y ^{5} - 8}{y - 1} = y^{9} + y^{8} + y^{7} + y^{6} + y^{5} + 8 y^{4} + 8 y^{3} + 8 y^{2} + 8 y + 8

= (y - 1) (y^{9} + y^{8} + y^{7} + y^{6} + y^{5} + 8 y^{4} + 8 y^{3} + 8 y^{2} + 8 y + 8)

Faktorisiere

y^{9} + y^{8} + y^{7} + y^{6} + y^{5} + 8 y^{4} + 8 y^{3} + 8 y^{2} + 8 y + 8 : (y^{4} + y^{3} + y^{2} + y + 1) (y^{5} + 8)

= (y - 1) (y^{4} + y^{3} + y^{2} + y + 1) (y^{5} + 8)

f a c t or f (x y)

f a c t or (x - 1)^{3} + 1

f a c t or (x - 5) (x - 5)

f a c t or x^{8} - 25

f a c t or 2 a x + 5 b x + 2 a y + 5 b y