What is factor m^2-n^2+4+4m-1-2n ?

The solution to factor m^2-n^2+4+4m-1-2n is m^2+4m+3-n^2-2n

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factor m^2-n^2+4+4m-1-2n

factor

m^{2} - n^{2} + 4 + 4 m - 1 - 2 n

m^{2} + 4 m + 3 - n^{2} - 2 n

Solution steps

m^{2} - n^{2} + 4 + 4 m - 1 - 2 n

Add/Subtract the numbers:

4 - 1 = 3

= m^{2} + 4 m + 3 - n^{2} - 2 n

[- 2.3]

13 (e^{3 x} cos (2 x))

[(a + 3 b) + 4 c]^{3}

x y + x y^{'} (x)

ln (e^{5} + e^{2})

What is factor m^2-n^2+4+4m-1-2n ?
The solution to factor m^2-n^2+4+4m-1-2n is m^2+4m+3-n^2-2n