What is (x^2-2x-3)/(x^2+5x+4) ?

The solution to (x^2-2x-3)/(x^2+5x+4) is (x-3)/(x+4)

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simplify (x^2-2x-3)/(x^2+5x+4)

simplify

\frac{x ^{2} - 2 x - 3}{x ^{2} + 5 x + 4}

\frac{x - 3}{x + 4}

Solution steps

\frac{x ^{2} - 2 x - 3}{x ^{2} + 5 x + 4}

Factor

x^{2} - 2 x - 3 : (x + 1) (x - 3)

= \frac{( x + 1 ) ( x - 3 )}{x ^{2} + 5 x + 4}

Factor

x^{2} + 5 x + 4 : (x + 1) (x + 4)

= \frac{( x + 1 ) ( x - 3 )}{( x + 1 ) ( x + 4 )}

Cancel the common factor:

x + 1

= \frac{x - 3}{x + 4}

\frac{7}{- 6}

5 (x + 1) - 2 (x^{2} - 4 x + 5)

sec^{2} (x) \cdot sec^{2} (x)

3 x + 5 - 4 x^{2} - 2 - x^{2} - 3 x + 1

- \frac{1}{2} \cdot \frac{5}{7}

What is (x^2-2x-3)/(x^2+5x+4) ?
The solution to (x^2-2x-3)/(x^2+5x+4) is (x-3)/(x+4)