What is 5(a+1)^2-(a+1)+4 ?

The solution to 5(a+1)^2-(a+1)+4 is 5a^2+9a+8

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simplify 5(a+1)^2-(a+1)+4

simplify

5 (a + 1)^{2} - (a + 1) + 4

5 a^{2} + 9 a + 8

Solution steps

5 (a + 1)^{2} - (a + 1) + 4

Apply the distributive law:

- (a + b) = - a - b

- (a + 1) = - a - 1

= 5 (a + 1)^{2} - a - 1 + 4

Expand

5 (a + 1)^{2} : 5 a^{2} + 10 a + 5

= 5 a^{2} + 10 a + 5 - a - 1 + 4

Group like terms

= 5 a^{2} + 10 a - a + 5 - 1 + 4

Add similar elements:

10 a - a = 9 a

= 5 a^{2} + 9 a + 5 - 1 + 4

Add the numbers:

5 - 1 + 4 = 8

= 5 a^{2} + 9 a + 8

\frac{11}{14} \div \frac{7}{22}

3 x - 10 x

36 x + 63

x + (x + 2)