What is factor x^4+6x^3+3x+140 ?

The solution to factor x^4+6x^3+3x+140 is (x+4)(x+5)(x^2-3x+7)

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factor x^4+6x^3+3x+140

factor

x^{4} + 6 x^{3} + 3 x + 140

(x + 4) (x + 5) (x^{2} - 3 x + 7)

Solution steps

x^{4} + 6 x^{3} + 3 x + 140

Use the rational root theorem

= (x + 4) \frac{x ^{4} + 6 x ^{3} + 3 x + 140}{x + 4}

\frac{x ^{4} + 6 x ^{3} + 3 x + 140}{x + 4} = x^{3} + 2 x^{2} - 8 x + 35

= (x + 4) (x^{3} + 2 x^{2} - 8 x + 35)

Factor

x^{3} + 2 x^{2} - 8 x + 35 : (x + 5) (x^{2} - 3 x + 7)

= (x + 4) (x + 5) (x^{2} - 3 x + 7)

\frac{4}{5} - \frac{1}{13}

2 x^{3} + 5 x^{2}

\frac{1}{5} \cdot \frac{5}{6}

- 2 (x - 6)

What is factor x^4+6x^3+3x+140 ?
The solution to factor x^4+6x^3+3x+140 is (x+4)(x+5)(x^2-3x+7)