What is (7p^2+3p)-(5p^2+4) ?

The solution to (7p^2+3p)-(5p^2+4) is 2p^2+3p-4

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simplify (7p^2+3p)-(5p^2+4)

simplify

(7 p^{2} + 3 p) - (5 p^{2} + 4)

2 p^{2} + 3 p - 4

Solution steps

(7 p^{2} + 3 p) - (5 p^{2} + 4)

Apply rule:

(a) = a

(7 p^{2} + 3 p) = 7 p^{2} + 3 p

= 7 p^{2} + 3 p - (5 p^{2} + 4)

Apply the distributive law:

- (a + b) = - a - b

- (5 p^{2} + 4) = - 5 p^{2} - 4

= 7 p^{2} + 3 p - 5 p^{2} - 4

Group like terms

= 7 p^{2} - 5 p^{2} + 3 p - 4

Add similar elements:

7 p^{2} - 5 p^{2} = 2 p^{2}

= 2 p^{2} + 3 p - 4

4 \cdot \frac{2}{7}

\frac{1}{x} + 2 x

(- 5 a^{2} b) (2 a b^{2} c) (- 3 b)

\frac{\frac{x + 9}{x + 3} - 2}{x - 3}

80 v^{2} u - 8 v^{3} + 40 v^{3}