What is (x^2+3x+2)/(x^2+4x+4) ?

The solution to (x^2+3x+2)/(x^2+4x+4) is (x+1)/(x+2)

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simplify (x^2+3x+2)/(x^2+4x+4)

simplify

\frac{x ^{2} + 3 x + 2}{x ^{2} + 4 x + 4}

\frac{x + 1}{x + 2}

Solution steps

\frac{x ^{2} + 3 x + 2}{x ^{2} + 4 x + 4}

Factor

x^{2} + 3 x + 2 : (x + 1) (x + 2)

= \frac{( x + 1 ) ( x + 2 )}{x ^{2} + 4 x + 4}

Factor

x^{2} + 4 x + 4 : (x + 2)^{2}

= \frac{( x + 1 ) ( x + 2 )}{( x + 2 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x + 2)^{2} = (x + 2) (x + 2)

= \frac{( x + 1 ) ( x + 2 )}{( x + 2 ) ( x + 2 )}

Cancel the common factor:

x + 2

= \frac{x + 1}{x + 2}

1.02 5^{6}

43 \cdot 2

(- 7) + (- 3)

e^{l o g_{e} (2)}

- 3 x^{2} - 21 x + 90

What is (x^2+3x+2)/(x^2+4x+4) ?
The solution to (x^2+3x+2)/(x^2+4x+4) is (x+1)/(x+2)