What is the answer to (x-5)(x+1)+(2x-5)(x+2)-(x+7)(3x-4)=2 ?

The answer to (x-5)(x+1)+(2x-5)(x+2)-(x+7)(3x-4)=2 is x= 1/2

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(x-5)(x+1)+(2x-5)(x+2)-(x+7)(3x-4)=2

(x - 5) (x + 1) + (2 x - 5) (x + 2) - (x + 7) (3 x - 4) = 2

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

(x - 5) (x + 1) + (2 x - 5) (x + 2) - (x + 7) (3 x - 4) = 2

Expand

(x - 5) (x + 1) + (2 x - 5) (x + 2) - (x + 7) (3 x - 4) : - 22 x + 13

- 22 x + 13 = 2

Move

13

to the right side

- 22 x = - 11

Divide both sides by

- 22

x = \frac{1}{2}

(5 x + 15) = (6 x - 10)

- 2 ∣ 5 - 4 x ∣ + 5 = 3

5 (2 x - 1) = 6

- 6 t - 3 < - 2 t - 19

- 6 x^{3} + 7 x^{2} - 1

What is the answer to (x-5)(x+1)+(2x-5)(x+2)-(x+7)(3x-4)=2 ?
The answer to (x-5)(x+1)+(2x-5)(x+2)-(x+7)(3x-4)=2 is x= 1/2
Solve for x: (x-5)(x+1)+(2x-5)(x+2)-(x+7)(3x-4)=2
The solution is x= 1/2