What is expand (x-3)(2x^2-4x+8) ?

The solution to expand (x-3)(2x^2-4x+8) is 2x^3-10x^2+20x-24

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expand (x-3)(2x^2-4x+8)

expand

(x - 3) (2 x^{2} - 4 x + 8)

2 x^{3} - 10 x^{2} + 20 x - 24

Solution steps

(x - 3) (2 x^{2} - 4 x + 8)

Distribute parentheses

= x \cdot 2 x^{2} + x (- 4 x) + x \cdot 8 - 3 \cdot 2 x^{2} - 3 (- 4 x) - 3 \cdot 8

Simplify

x \cdot 2 x^{2} + x (- 4 x) + x \cdot 8 - 3 \cdot 2 x^{2} - 3 (- 4 x) - 3 \cdot 8 : 2 x^{3} - 10 x^{2} + 20 x - 24

= 2 x^{3} - 10 x^{2} + 20 x - 24

(x tan (x))^{2}

6 \cdot 1 0^{- 7}

5 a^{2} + 7 a + 2

\frac{2}{3} (8)

\frac{x ^{4} - y ^{4}}{x + y}

What is expand (x-3)(2x^2-4x+8) ?
The solution to expand (x-3)(2x^2-4x+8) is 2x^3-10x^2+20x-24