What is ((2vq^6)/(qv^3))^{-2} ?

The solution to ((2vq^6)/(qv^3))^{-2} is (v^4)/(4q^{10)}

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simplify ((2vq^6)/(qv^3))^{-2}

simplify

(\frac{2 v q ^{6}}{q v ^{3}})^{- 2}

\frac{v ^{4}}{4 q ^{10}}

Solution steps

(\frac{2 v q ^{6}}{q v ^{3}})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{2 v q ^{6}}{q v ^{3}})^{- 2} = \frac{1}{( \frac{2 v q ^{6}}{q v ^{3}} ) ^{2}}

= \frac{1}{( \frac{2 v q ^{6}}{q v ^{3}} ) ^{2}}

Simplify

(\frac{2 v q ^{6}}{q v ^{3}})^{2} : \frac{4 q ^{10}}{v ^{4}}

= \frac{1}{\frac{4 q ^{10}}{v ^{4}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{v ^{4}}{4 q ^{10}}

4 - 3 (1.9999)^{3}

(3 x - 12) (x + 4)

(2 + 3 i) + (4 - 2 i)

\frac{72}{25}

(z + 1)^{4}

What is ((2vq^6)/(qv^3))^{-2} ?
The solution to ((2vq^6)/(qv^3))^{-2} is (v^4)/(4q^{10)}