What are the solutions to the equation (4x-3)^2+7=39 ?

The solutions to the equation (4x-3)^2+7=39 are x=(4sqrt(2)+3)/4 ,x=(-4sqrt(2)+3)/4

Find the zeros of (4x-3)^2+7=39

The zeros of (4x-3)^2+7=39 are x=(4sqrt(2)+3)/4 ,x=(-4sqrt(2)+3)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(4 x - 3)^{2} + 7 = 39

x = \frac{4 2 + 3}{4}, x = \frac{- 4 2 + 3}{4}

Decimal Notation

x = 2.16421 \dots, x = - 0.66421 \dots

Solution steps

(4 x - 3)^{2} + 7 = 39

Move

7

to the right side

(4 x - 3)^{2} = 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 3 = 32 : x = \frac{4 2 + 3}{4}

Solve

4 x - 3 = - 32 : x = \frac{- 4 2 + 3}{4}

The solutions to the quadratic equation are:

x = \frac{4 2 + 3}{4}, x = \frac{- 4 2 + 3}{4}

∣ x - 5 ∣ = 6

(\frac{7}{2})^{3}

1 x^{2} + 4 x + 1 = 0

∣ 7 x + 1 ∣ + 8 = 8

- \frac{2}{5} (15 - 20 d + 5 c)

What are the solutions to the equation (4x-3)^2+7=39 ?
The solutions to the equation (4x-3)^2+7=39 are x=(4sqrt(2)+3)/4 ,x=(-4sqrt(2)+3)/4
Find the zeros of (4x-3)^2+7=39
The zeros of (4x-3)^2+7=39 are x=(4sqrt(2)+3)/4 ,x=(-4sqrt(2)+3)/4