簡約 (3x-2)(4x+5)-(6x+1)(2x-10)-63x

解

簡約

(3 x - 2) (4 x + 5) - (6 x + 1) (2 x - 10) - 63 x

2 x

解答ステップ

(3 x - 2) (4 x + 5) - (6 x + 1) (2 x - 10) - 63 x

拡張

(3 x - 2) (4 x + 5) : 12 x^{2} + 7 x - 10

= 12 x^{2} + 7 x - 10 - (6 x + 1) (2 x - 10) - 63 x

拡張

- (6 x + 1) (2 x - 10) : - 12 x^{2} + 58 x + 10

= 12 x^{2} + 7 x - 10 - 12 x^{2} + 58 x + 10 - 63 x

条件のようなグループ

= 12 x^{2} - 12 x^{2} + 7 x + 58 x - 63 x - 10 + 10

類似した元を足す:

12 x^{2} - 12 x^{2} = 0

= 7 x + 58 x - 63 x - 10 + 10

類似した元を足す:

7 x + 58 x - 63 x = 2 x

= 2 x - 10 + 10

数を足す:

- 10 + 10 = 0

= 2 x