What are the solutions to the equation 6x^2+30x-36=0 ?

The solutions to the equation 6x^2+30x-36=0 are x=1,x=-6

Find the zeros of 6x^2+30x-36=0

The zeros of 6x^2+30x-36=0 are x=1,x=-6

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6 x^{2} + 30 x - 36 = 0

x = 1, x = - 6

Solution steps

6 x^{2} + 30 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 6 ( - 36 )}{2 \cdot 6}

3 0^{2} - 4 \cdot 6 (- 36) = 42

x_{1, 2} = \frac{- 30 \pm 42}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 30 + 42}{2 \cdot 6}, x_{2} = \frac{- 30 - 42}{2 \cdot 6}

x = \frac{- 30 + 42}{2 \cdot 6} : 1

x = \frac{- 30 - 42}{2 \cdot 6} : - 6

The solutions to the quadratic equation are:

x = 1, x = - 6

\frac{4 ^{- 3}}{4 ^{- 8}}

- 16 (x^{2} - 8 x - 9)

5 x^{2} + 10 x - 7 = 0

(x + 2)^{2} > 5

What are the solutions to the equation 6x^2+30x-36=0 ?
The solutions to the equation 6x^2+30x-36=0 are x=1,x=-6
Find the zeros of 6x^2+30x-36=0
The zeros of 6x^2+30x-36=0 are x=1,x=-6