What are the solutions to the equation 7x^2+5=0 ?

The solutions to the equation 7x^2+5=0 are x=sqrt(5/7)i,x=-sqrt(5/7)i

Find the zeros of 7x^2+5=0

The zeros of 7x^2+5=0 are x=sqrt(5/7)i,x=-sqrt(5/7)i

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7 x^{2} + 5 = 0

x = \frac{5}{7} i, x = - \frac{5}{7} i

Solution steps

7 x^{2} + 5 = 0

Move

5

to the right side

7 x^{2} = - 5

Divide both sides by

7

x^{2} = - \frac{5}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{5}{7}, x = - - \frac{5}{7}

- \frac{5}{7} = \frac{5}{7} i

- - \frac{5}{7} = - \frac{5}{7} i

x = \frac{5}{7} i, x = - \frac{5}{7} i

\frac{5}{\frac{19}{6}}

\frac{2}{2}

(3 + 2 i) - (3 - 2 i)

2 ∣ x + 9 ∣ - 4 = 12

- 3 x^{2} - 10 x - 8 = 0

What are the solutions to the equation 7x^2+5=0 ?
The solutions to the equation 7x^2+5=0 are x=sqrt(5/7)i,x=-sqrt(5/7)i
Find the zeros of 7x^2+5=0
The zeros of 7x^2+5=0 are x=sqrt(5/7)i,x=-sqrt(5/7)i