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Beliebt Algebra >

1/((x-2))-1/((x+1))>= 0

Lösung

\frac{1}{( x - 2 )} - \frac{1}{( x + 1 )} \geq 0

Lösung

x < - 1 or x > 2

+1

Intervall-Notation

(- \infty, - 1) \cup (2, \infty)

Schritte zur Lösung

\frac{1}{x - 2} - \frac{1}{x + 1} \geq 0

Rewrite in standard form

\frac{1}{( x - 2 ) ( x + 1 )} \geq 0

Wenn

\frac{1}{a} \geq 0

dann

a > 0

(x - 2) (x + 1) > 0

Identifiziere die Intervalle

x < - 1 or x > 2

Graph

Beliebte Beispiele

(3x-1)(x+5)-1<= 3(x-2)+21x

(3 x - 1) (x + 5) - 1 \leq 3 (x - 2) + 21 x

\frac{4}{( 3 x - 2 )} \leq - 2

3 x^{2} - 8 < - 2 x

((x-1)(x-2)^3(x-4)^2)/(x+3)>= 0

\frac{( x - 1 ) ( x - 2 ) ^{3} ( x - 4 ) ^{2}}{x + 3} \geq 0

x^{3} + 5 x^{2} + 4 x > 0