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Beliebt Algebra >

a(a-2)>= 2(a+6)

Lösung

a (a - 2) \geq 2 (a + 6)

Lösung

a \leq - 2 or a \geq 6

+1

Intervall-Notation

(- \infty, - 2] \cup [6, \infty)

Schritte zur Lösung

a (a - 2) \geq 2 (a + 6)

Rewrite in standard form

a^{2} - 4 a - 12 \geq 0

Faktorisiere

a^{2} - 4 a - 12 : (a + 2) (a - 6)

(a + 2) (a - 6) \geq 0

Identifiziere die Intervalle

a \leq - 2 or a \geq 6

Graph

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