6x^2+7x-3=0,x_{1}=x_{2}

解

6 x^{2} + 7 x - 3 = 0, x_{1} = x_{2}

(x = \frac{1}{3}, x = - \frac{3}{2}, x_{1} \in R, x_{1} \in R, x_{2} = x_{1} x_{2} = x_{1})

解答ステップ

[6 x^{2} + 7 x - 3 = 0 x_{1} = x_{2}]

解く

6 x^{2} + 7 x - 3 = 0 : x = \frac{1}{3}, x = - \frac{3}{2}

以下のために

x_{1} = x_{2}

を解く:

x = \frac{1}{3} : (x = \frac{1}{3}, x_{1} \in R, x_{2} = x_{1})

以下のために

x_{1} = x_{2}

を解く:

x = - \frac{3}{2} : (x = - \frac{3}{2}, x_{1} \in R, x_{2} = x_{1})

元のequationに当てはめて解を検算する

ゆえに,

6 x^{2} + 7 x - 3 = 0, x_{1} = x_{2}

の最終的な解は

(x = \frac{1}{3}, x = - \frac{3}{2}, x_{1} \in R, x_{1} \in R, x_{2} = x_{1} x_{2} = x_{1})