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受欢迎的代数 >

solvefor x,(log_{2}(x))^2= 1/f

解答

求解

x, (lo g_{2} (x))^{2} = \frac{1}{f}

解答

x = 2^{\frac{1}{f}} {f > 0}, x = 2^{- \frac{1}{f}} {f < 0 or f > 0}

求解步骤

(lo g_{2} (x))^{2} = \frac{1}{f}

用

lo g_{2} (x) = u

改写方程式

u^{2} = \frac{1}{f}

解

u^{2} = \frac{1}{f} : u = \frac{1}{f}, u = - \frac{1}{f}

u = \frac{1}{f}, u = - \frac{1}{f}

代回

u = lo g_{2} (x)

，求解

x

解

lo g_{2} (x) = \frac{1}{f} : x = 2^{\frac{1}{f}}

解

lo g_{2} (x) = - \frac{1}{f} : x = 2^{- \frac{1}{f}}

x = 2^{\frac{1}{f}}, x = 2^{- \frac{1}{f}}

验证解:

x = 2^{\frac{1}{f}} {f > 0}, x = 2^{- \frac{1}{f}} {f < 0 or f > 0}

解为

x = 2^{\frac{1}{f}} {f > 0}, x = 2^{- \frac{1}{f}} {f < 0 or f > 0}

作图

流行的例子

2log_{10}(x)=3+log_{10}(x)

2 lo g_{10} (x) = 3 + lo g_{10} (x)

log_{10}(10m)=4

lo g_{10} (10 m) = 4

log_{5}(x^2+x+5)=2

lo g_{5} (x^{2} + x + 5) = 2

((log_{10}(2x^2+1)))/((log_{10)(x+1))}=2

\frac{( lo g _{10} ( 2 x ^{2} + 1 ) )}{( lo g _{10} ( x + 1 ) )} = 2

log_{4}(x^2-25)=1+log_{4}(x-1)

lo g_{4} (x^{2} - 25) = 1 + lo g_{4} (x - 1)