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Frequently Asked Questions (FAQ)
What are the solutions to the equation 4(x-7)^2-42=-22 ?
- The solutions to the equation 4(x-7)^2-42=-22 are x=sqrt(5)+7,x=-sqrt(5)+7
Find the zeros of 4(x-7)^2-42=-22
- The zeros of 4(x-7)^2-42=-22 are x=sqrt(5)+7,x=-sqrt(5)+7