|2x-x^2-3x|=1

解

2 x - x^{2} - 3 x = 1

x = - \frac{1 + 5}{2} or x = \frac{5 - 1}{2}

十進法表記

x = - 1.61803 \dots, x = 0.61803 \dots

解答ステップ

2 x - x^{2} - 3 x = 1

絶対規則を適用する:

∣ u ∣ = a, a > 0

の場合は

u = a

u = - a

2 x - x^{2} - 3 x = - 1 or 2 x - x^{2} - 3 x = 1

2 x - x^{2} - 3 x = - 1 or 2 x - x^{2} - 3 x = 1

(x = - \frac{1 + 5}{2} or x = \frac{5 - 1}{2}) or 解なし

x = - \frac{1 + 5}{2} or x = \frac{5 - 1}{2}