|x^2-1|-2x=1

解答

x^{2} - 1 - 2 x = 1

x = 0 or x = 1 + 3

十进制

x = 0, x = 2.73205 \dots

求解步骤

x^{2} - 1 - 2 x = 1

找到正负区间

x \leq - 1, - 1 < x < 1, x \geq 1

对每个区间解不等式

无解 or x = 0 or x = 1 + 3

x = 0 or x = 1 + 3

∣ 5 x - 6 ∣ = x^{2}

1 + ∣ x ∣ = ∣ x + 1 ∣

∣ x - 1 ∣ + ∣ x - 2 ∣ + ∣ x - 3 ∣ = 2

∣ x - 1 ∣ + ∣ x - 2 ∣ + ∣ x - 3 ∣ = 6

x^{2} + x + 1 - x^{2} - x - 1 = 0