What is the answer to (x^{0.16})+80=122 ?

The answer to (x^{0.16})+80=122 is x=42^6\sqrt[4]{42},x=-42^6\sqrt[4]{42}

Solve for x: (x^{0.16})+80=122

The solution is x=42^6\sqrt[4]{42},x=-42^6\sqrt[4]{42}

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(x^{0.16}) + 80 = 122

x = 4 2^{6} 442, x = - 4 2^{6} 442

Decimal

x = 13973592205.424616, x = - 13973592205.424616

Solution steps

(x^{0.16}) + 80 = 122

Move

80

to the right side

x^{0.16} = 42

Take both sides of the equation to the power of

25 : x^{4} = 4 2^{25}

x^{4} = 4 2^{25}

Solve

x^{4} = 4 2^{25} : x = 4 2^{6} 442, x = - 4 2^{6} 442

x = 4 2^{6} 442, x = - 4 2^{6} 442

Verify Solutions:

x = 4 2^{6} 442

True

, x = - 4 2^{6} 442

True

The solutions are

x = 4 2^{6} 442, x = - 4 2^{6} 442

y - 19 = 2

x + 7 + x + 2 = \frac{15}{( x + 7 )}

3 x^{2} + 7 5 x + 2 = 0

\frac{1}{3 \cdot x - 1 + 2} = 5

so l v e f or a, a \cdot b^{2} = b \cdot a

What is the answer to (x^{0.16})+80=122 ?
The answer to (x^{0.16})+80=122 is x=42^6\sqrt[4]{42},x=-42^6\sqrt[4]{42}
Solve for x: (x^{0.16})+80=122
The solution is x=42^6\sqrt[4]{42},x=-42^6\sqrt[4]{42}