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受欢迎的代数 >

solvefor a, 1/a+1/b = 3/2020

解答

求解

a, \frac{1}{a} + \frac{1}{b} = \frac{3}{2020}

解答

a = - \frac{2020 b}{2020 - 3 b}; b \neq = 0, b \neq = \frac{2020}{3}

求解步骤

\frac{1}{a} + \frac{1}{b} = \frac{3}{2020}

在两边乘以

a

1 + \frac{a}{b} = \frac{3}{2020} a

将

1

到右边

\frac{a}{b} = \frac{3}{2020} a - 1

乘以最小公倍数

2020 a = 3 ab - 2020 b; b \neq = 0

将

3 ab

para o lado esquerdo

2020 a - 3 ab = - 2020 b; b \neq = 0

分解

2020 a - 3 ab : a (2020 - 3 b)

a (2020 - 3 b) = - 2020 b; b \neq = 0

两边除以

2020 - 3 b; b \neq = 0, b \neq = \frac{2020}{3}

a = - \frac{2020 b}{2020 - 3 b}; b \neq = 0, b \neq = \frac{2020}{3}

作图

流行的例子

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\frac{( 216 x ^{3} ) + 1}{( 27 x ^{3} )} = 135

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0.3 (x + 1) = \frac{1}{2 ( x - 1 )}

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