|x|+| x/((x-1))|=((x^2))/(|x-1|)

解答

∣ x ∣ + \frac{x}{( x - 1 )} = \frac{( x ^{2} )}{∣ x - 1 ∣}

x = 0 or x \geq 1

求解步骤

∣ x ∣ + \frac{x}{( x - 1 )} = \frac{( x ^{2} )}{∣ x - 1 ∣}

化简

∣ x ∣ + \frac{∣ x ∣}{∣ x - 1 ∣} = \frac{x ^{2}}{∣ x - 1 ∣}

在两边乘以

∣ x - 1 ∣

∣ x ∣ ∣ x - 1 ∣ + ∣ x ∣ = x^{2}

解

∣ x ∣ ∣ x - 1 ∣ + ∣ x ∣ = x^{2} : x = 0 or x \geq 1

x = 0 or x \geq 1

so l v e f or a, \frac{1}{a} + \frac{1}{b} + \frac{1}{c} = 1

so l v e f or x, \frac{7}{x} - \frac{6}{y} = \frac{11}{2}

so l v e f or x, \frac{7}{x} = - y

so l v e f or a, \frac{( - b )}{a} = \frac{( 2 )}{3}

\frac{4.3}{x} = 0.002