solvefor m, 3/4 = 1/(n^2)-1/(m^2)

Lösung

löse nach

m, \frac{3}{4} = \frac{1}{n ^{2}} - \frac{1}{m ^{2}}

m = i \frac{2 n - 4 + 3 n ^{2}}{- 4 + 3 n ^{2}}, m = - i \frac{2 n - 4 + 3 n ^{2}}{- 4 + 3 n ^{2}}; n \neq = \frac{2}{3}, n \neq = - \frac{2}{3}

Schritte zur Lösung

\frac{3}{4} = \frac{1}{n ^{2}} - \frac{1}{m ^{2}}

Multipliziere mit dem kleinsten gemeinsamen Multiplikator

3 m^{2} n^{2} = 4 m^{2} - 4 n^{2}

Löse

3 m^{2} n^{2} = 4 m^{2} - 4 n^{2} : m = i \frac{2 n - 4 + 3 n ^{2}}{- 4 + 3 n ^{2}}, m = - i \frac{2 n - 4 + 3 n ^{2}}{- 4 + 3 n ^{2}}; n \neq = \frac{2}{3}, n \neq = - \frac{2}{3}

m = i \frac{2 n - 4 + 3 n ^{2}}{- 4 + 3 n ^{2}}, m = - i \frac{2 n - 4 + 3 n ^{2}}{- 4 + 3 n ^{2}}; n \neq = \frac{2}{3}, n \neq = - \frac{2}{3}

\frac{1}{a} + b + x = \frac{1}{a} + \frac{1}{b} + \frac{1}{x}

\frac{x ^{2}}{x - 3} = \frac{x}{x - 3}

\frac{3 ( x + 5 ) + 2}{( x + 5 )} = 5

(\frac{x + 1}{x})^{2} - 2 (\frac{x - 1}{x + 4}) = 11

so l v e f or a, \frac{1}{a} + \frac{1}{b} = \frac{5}{6}