(2^2)^m-(2^2)^n=240

Lösung

(2^{2})^{m} - (2^{2})^{n} = 240

n = \frac{ln ( - 240 + 2 ^{2 m} )}{2 ln ( 2 )}

Schritte zur Lösung

(2^{2})^{m} - (2^{2})^{n} = 240

Wende Exponentenregel an

2 n ln (2) = ln (- 240 + 2^{2 m})

Löse

2 n ln (2) = ln (- 240 + 2^{2 m}) : n = \frac{ln ( - 240 + 2 ^{2 m} )}{2 ln ( 2 )}

n = \frac{ln ( - 240 + 2 ^{2 m} )}{2 ln ( 2 )}

x^{x} = 2^{2084}

5^{x} - 24 = \frac{5 ^{2}}{5} x

5^{(x - 1)} + 5^{(x - 2)} = 30

(\frac{1}{2})^{\frac{t}{2}} = 64

3^{2 x - 1} \cdot 2 7^{3 - x} = 1