4^{3x-1}=3(5^x)

Lösung

4^{3 x - 1} = 3 (5^{x})

x = \frac{ln ( 12 )}{6 ln ( 2 ) - ln ( 5 )}

Dezimale

x = 0.97468 \dots

Schritte zur Lösung

4^{3 x - 1} = 3 (5^{x})

Wende Exponentenregel an

(3 x - 1) ln (4) = ln (3) + x ln (5)

Löse

(3 x - 1) ln (4) = ln (3) + x ln (5) : x = \frac{ln ( 12 )}{6 ln ( 2 ) - ln ( 5 )}

x = \frac{ln ( 12 )}{6 ln ( 2 ) - ln ( 5 )}

3 = 2^{x}

256 = 2^{x}

(\frac{1}{3})^{13 - 3 x} = 9

2^{x} - 2^{\frac{x}{2} + 1} = 8

7^{x} = 5^{x}