e^{4t+2}=4e^{2-t}

解答

e^{4 t + 2} = 4 e^{2 - t}

t = \frac{2 ln ( 2 )}{5}

十进制

t = 0.27725 \dots

求解步骤

e^{4 t + 2} = 4 e^{2 - t}

使用指数运算法则

4 t + 2 = ln (4) + 2 - t

解

4 t + 2 = ln (4) + 2 - t : t = \frac{2 ln ( 2 )}{5}

t = \frac{2 ln ( 2 )}{5}

((2^{x})^{+})^{2} + 2^{x} = 5

(1.03)^{n} = 2

5^{2 x + 2} = 3^{5 x - 1}

\frac{( 8 \cdot 2 ^{n} + 2 \cdot 2 ^{n} )}{( - 2 ^{n + 1} + 4 \cdot 2 ^{n} )} = 5^{n}

4^{x} + 4^{x} + 2^{x} = 1