2^{3x+1}=3^{x-2}

Lösung

2^{3 x + 1} = 3^{x - 2}

x = - \frac{ln ( 18 )}{3 ln ( 2 ) - ln ( 3 )}

Dezimale

x = - 2.94686 \dots

Schritte zur Lösung

2^{3 x + 1} = 3^{x - 2}

Wende Exponentenregel an

(3 x + 1) ln (2) = (x - 2) ln (3)

Löse

(3 x + 1) ln (2) = (x - 2) ln (3) : x = - \frac{ln ( 18 )}{3 ln ( 2 ) - ln ( 3 )}

x = - \frac{ln ( 18 )}{3 ln ( 2 ) - ln ( 3 )}

5^{x} = 8

4^{x} + 1 6^{x} = 272

2^{x + 2} - 2^{x} = 4

4 9^{x + 1} + 7^{2 x} = 350

so l v e f or x, 2^{x} = 3^{y}