solvefor x,((f*f(x^2)))/((1+[f]^2))= 1/2

Lösung

löse nach

x, \frac{( f \cdot f ( x ^{2} ) )}{( 1 + [ f ] ^{2} )} = \frac{1}{2}

x = \frac{1 + f ^{2}}{2 f}, x = - \frac{1 + f ^{2}}{2 f}; f \neq = i, f \neq = - i, f \neq = 0

Schritte zur Lösung

\frac{( ff ( x ^{2} ) )}{( 1 + [ f ] ^{2} )} = \frac{1}{2}

Multipliziere beide Seiten mit

1 + [f]^{2}

f^{2} x^{2} = \frac{1 + f ^{2}}{2}; f \neq = i, f \neq = - i

Teile beide Seiten durch

f^{2}; f \neq = i, f \neq = - i, f \neq = 0

x^{2} = \frac{1 + f ^{2}}{2 f ^{2}}; f \neq = i, f \neq = - i, f \neq = 0

Für

x^{2} = f (a)

sind die Lösungen

x = f (a), - f (a)

x = \frac{1 + f ^{2}}{2 f ^{2}}, x = - \frac{1 + f ^{2}}{2 f ^{2}}; f \neq = i, f \neq = - i, f \neq = 0

Vereinfache

\frac{1 + f ^{2}}{2 f ^{2}} : \frac{1 + f ^{2}}{2 f}

Vereinfache

- \frac{1 + f ^{2}}{2 f ^{2}} : - \frac{1 + f ^{2}}{2 f}

x = \frac{1 + f ^{2}}{2 f}, x = - \frac{1 + f ^{2}}{2 f}; f \neq = i, f \neq = - i, f \neq = 0

2 p + p^{2} = 1358

x^{2} + (m - 1) \cdot x + 2 m - 6 = 0

x^{2} = - 3, x^{1} = 7

25 m^{2} - 54 m + 128 = 0

so l v e f or a, a^{2} + b^{2} - 2 (3 a + 2 b) + 13 = 0