solvefor x,k*x^2-10x+3=0

解

x, k \cdot x^{2} - 10 x + 3 = 0

x = \frac{5 + - 3 k + 25}{k}, x = \frac{5 - - 3 k + 25}{k}; k \neq = 0

解答ステップ

k x^{2} - 10 x + 3 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 k \cdot 3}{2 k}

簡素化

(- 10)^{2} - 4 k \cdot 3 : 2 25 - 3 k

x_{1, 2} = \frac{- ( - 10 ) \pm 2 25 - 3 k}{2 k}; k \neq = 0

解を分離する

x_{1} = \frac{- ( - 10 ) + 2 25 - 3 k}{2 k}, x_{2} = \frac{- ( - 10 ) - 2 25 - 3 k}{2 k}

x = \frac{- ( - 10 ) + 2 25 - 3 k}{2 k} : \frac{5 + - 3 k + 25}{k}

x = \frac{- ( - 10 ) - 2 25 - 3 k}{2 k} : \frac{5 - - 3 k + 25}{k}

二次equationの解:

x = \frac{5 + - 3 k + 25}{k}, x = \frac{5 - - 3 k + 25}{k}; k \neq = 0