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人気のある代数 >

solvefor x,x^2+(y-x 2/3)^2=1

解

解く

x, x^{2} + (y - x \frac{2}{3})^{2} = 1

解

x = \frac{3 ( 2 y + - 9 y ^{2} + 13 )}{13}, x = \frac{3 ( 2 y - - 9 y ^{2} + 13 )}{13}

解答ステップ

x^{2} + (y - x \frac{2}{3})^{2} = 1

拡張

x^{2} + (y - x \frac{2}{3})^{2} : \frac{13}{9} x^{2} - \frac{4}{3} x y + y^{2}

\frac{13}{9} x^{2} - \frac{4}{3} x y + y^{2} = 1

1

を左側に移動します

\frac{13}{9} x^{2} - \frac{4}{3} x y + y^{2} - 1 = 0

標準的な形式で書く

a x^{2} + b x + c = 0

\frac{13 x ^{2}}{9} - \frac{4 y x}{3} + y^{2} - 1 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - \frac{4 y}{3} ) \pm ( - \frac{4 y}{3} ) ^{2} - 4 \cdot \frac{13}{9} ( y ^{2} - 1 )}{2 \cdot \frac{13}{9}}

簡素化

(- \frac{4 y}{3})^{2} - 4 \cdot \frac{13}{9} (y^{2} - 1) : \frac{2 - 9 y ^{2} + 13}{3}

x_{1, 2} = \frac{- ( - \frac{4 y}{3} ) \pm \frac{2 - 9 y ^{2} + 13}{3}}{2 \cdot \frac{13}{9}}

解を分離する

x_{1} = \frac{- ( - \frac{4 y}{3} ) + \frac{2 - 9 y ^{2} + 13}{3}}{2 \cdot \frac{13}{9}}, x_{2} = \frac{- ( - \frac{4 y}{3} ) - \frac{2 - 9 y ^{2} + 13}{3}}{2 \cdot \frac{13}{9}}

x = \frac{- ( - \frac{4 y}{3} ) + \frac{2 - 9 y ^{2} + 13}{3}}{2 \frac{13}{9}} : \frac{3 ( 2 y + - 9 y ^{2} + 13 )}{13}

x = \frac{- ( - \frac{4 y}{3} ) - \frac{2 - 9 y ^{2} + 13}{3}}{2 \frac{13}{9}} : \frac{3 ( 2 y - - 9 y ^{2} + 13 )}{13}

二次equationの解:

x = \frac{3 ( 2 y + - 9 y ^{2} + 13 )}{13}, x = \frac{3 ( 2 y - - 9 y ^{2} + 13 )}{13}

グラフ

人気の例

2((x+1)/3)^2= 1/2

2 (\frac{x + 1}{3})^{2} = \frac{1}{2}

((43)/(42.5))n^2-n^2=3

(\frac{43}{42.5}) n^{2} - n^{2} = 3

b(x)=-9x-6+4x^2

b (x) = - 9 x - 6 + 4 x^{2}

solvefor x,x^2+4xy-y^2+3x-8y+2=0

so l v e f or x, x^{2} + 4 x y - y^{2} + 3 x - 8 y + 2 = 0

4.9t^2+294t-2450=0

4.9 t^{2} + 294 t - 2450 = 0