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受欢迎的代数 >

(d-x)^2=2x^2

解答

(d - x)^{2} = 2 x^{2}

解答

x = - (1 + 2) d, x = - (1 - 2) d

求解步骤

(d - x)^{2} = 2 x^{2}

展开

(d - x)^{2} : d^{2} - 2 d x + x^{2}

d^{2} - 2 d x + x^{2} = 2 x^{2}

将

2 x^{2}

para o lado esquerdo

d^{2} - 2 d x - x^{2} = 0

改写成标准形式

a x^{2} + b x + c = 0

- x^{2} - 2 d x + d^{2} = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 2 d ) \pm ( - 2 d ) ^{2} - 4 ( - 1 ) d ^{2}}{2 ( - 1 )}

化简

(- 2 d)^{2} - 4 (- 1) d^{2} : 22 d

x_{1, 2} = \frac{- ( - 2 d ) \pm 2 2 d}{2 ( - 1 )}

将解分隔开

x_{1} = \frac{- ( - 2 d ) + 2 2 d}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 d ) - 2 2 d}{2 ( - 1 )}

x = \frac{- ( - 2 d ) + 2 2 d}{2 ( - 1 )} : - (1 + 2) d

x = \frac{- ( - 2 d ) - 2 2 d}{2 ( - 1 )} : - (1 - 2) d

二次方程组的解是:

x = - (1 + 2) d, x = - (1 - 2) d

作图

流行的例子

(a+b)^2x^2+(a-b)^2=0

(a + b)^{2} x^{2} + (a - b)^{2} = 0

solvefor x,maxz=6x^1+4x^2

so l v e f or x, ma x z = 6 x^{1} + 4 x^{2}

solvefor x,f(x-2)=x^2+15

so l v e f or x, f (x - 2) = x^{2} + 15

solvefor x,(x-2)^2+(y-3)^2+(z+4)^2=0

so l v e f or x, (x - 2)^{2} + (y - 3)^{2} + (z + 4)^{2} = 0

4(n-2)4(n-2)=12

4 (n - 2) 4 (n - 2) = 12