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人気のある代数 >

(x-1)^2-(2x+2)^2=0

解

(x - 1)^{2} - (2 x + 2)^{2} = 0

解

x = - 3, x = - \frac{1}{3}

+1

十進法表記

x = - 3, x = - 0.33333 \dots

解答ステップ

(x - 1)^{2} - (2 x + 2)^{2} = 0

拡張

(x - 1)^{2} - (2 x + 2)^{2} : - 3 x^{2} - 10 x - 3

- 3 x^{2} - 10 x - 3 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 3 ) ( - 3 )}{2 ( - 3 )}

(- 10)^{2} - 4 (- 3) (- 3) = 8

x_{1, 2} = \frac{- ( - 10 ) \pm 8}{2 ( - 3 )}

解を分離する

x_{1} = \frac{- ( - 10 ) + 8}{2 ( - 3 )}, x_{2} = \frac{- ( - 10 ) - 8}{2 ( - 3 )}

x = \frac{- ( - 10 ) + 8}{2 ( - 3 )} : - 3

x = \frac{- ( - 10 ) - 8}{2 ( - 3 )} : - \frac{1}{3}

二次equationの解:

x = - 3, x = - \frac{1}{3}

グラフ

人気の例

2=(y/(2-3))(y-2)

2 = (\frac{y}{2 - 3}) (y - 2)

solvefor x,a*x^2+b*y^2+z^2=1

so l v e f or x, a \cdot x^{2} + b \cdot y^{2} + z^{2} = 1

(a-b)x^2+(b-c)x+(c-a)=0

(a - b) x^{2} + (b - c) x + (c - a) = 0

x^2-2(a^2+b^2)x+(a^2-b^2)=0

x^{2} - 2 (a^{2} + b^{2}) x + (a^{2} - b^{2}) = 0

solvefor x,p^3-(x^2+xy+y^2)*p+xy(x+y)=0

so l v e f or x, p^{3} - (x^{2} + x y + y^{2}) \cdot p + x y (x + y) = 0