x^3=(-7)/2

Lösung

x^{3} = \frac{- 7}{2}

x = - 3 \frac{7}{2}, x = - \frac{3 7 ( - 1 + 3 i )}{2 3 2}, x = - \frac{3 7 ( - 1 - 3 i )}{2 3 2}

Schritte zur Lösung

x^{3} = \frac{- 7}{2}

Wende Bruchregel an:

\frac{- a}{b} = - \frac{a}{b}

x^{3} = - \frac{7}{2}

Für

x^{3} = f (a)

sind die Lösungen

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

x = 3 - \frac{7}{2}, x = 3 - \frac{7}{2} \frac{- 1 + 3 i}{2}, x = 3 - \frac{7}{2} \frac{- 1 - 3 i}{2}

3 - \frac{7}{2} = - 3 \frac{7}{2}

Vereinfache

3 - \frac{7}{2} \frac{- 1 + 3 i}{2} : - \frac{3 7 ( - 1 + 3 i )}{2 3 2}

Vereinfache

3 - \frac{7}{2} \frac{- 1 - 3 i}{2} : - \frac{3 7 ( - 1 - 3 i )}{2 3 2}

x = - 3 \frac{7}{2}, x = - \frac{3 7 ( - 1 + 3 i )}{2 3 2}, x = - \frac{3 7 ( - 1 - 3 i )}{2 3 2}

x^{4} + 3 x^{3} - 12 x^{2} + 2 x - 1 = 0

3 x^{3} + x - 10 = 0

x (x - 1) (x + 2)^{3} = 0

14 x^{13} - 14 = 0

x^{3} + 3 x^{2} + 6 x + 5 = 0