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Beliebt Algebra >

d(x^3+8)-(x+2)(x-4)=0

Lösung

d (x^{3} + 8) - (x + 2) (x - 4) = 0

Lösung

x = - 2, x = \frac{1 + 2 d + - 12 d ^{2} - 12 d + 1}{2 d}, x = \frac{1 + 2 d - - 12 d ^{2} - 12 d + 1}{2 d}; d \neq = 0

Schritte zur Lösung

d (x^{3} + 8) - (x + 2) (x - 4) = 0

Faktorisiere

d (x^{3} + 8) - (x + 2) (x - 4) : (x + 2) (- x + d x^{2} - 2 d x + 4 d + 4)

(x + 2) (- x + d x^{2} - 2 d x + 4 d + 4) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

x + 2 = 0 or - x + d x^{2} - 2 d x + 4 d + 4 = 0

Löse

x + 2 = 0 : x = - 2

Löse

- x + d x^{2} - 2 d x + 4 d + 4 = 0 : x = \frac{1 + 2 d + - 12 d ^{2} - 12 d + 1}{2 d}, x = \frac{1 + 2 d - - 12 d ^{2} - 12 d + 1}{2 d}; d \neq = 0

Die Lösungen sind

x = - 2, x = \frac{1 + 2 d + - 12 d ^{2} - 12 d + 1}{2 d}, x = \frac{1 + 2 d - - 12 d ^{2} - 12 d + 1}{2 d}; d \neq = 0

Graph

Beliebte Beispiele

(x - 1)^{3} = \frac{1}{8}

(2 x + 3)^{3} = - 16

log_{10}(10)(x^3+5)=3log_{10}(10)(x+2)

lo g_{10} (10) (x^{3} + 5) = 3 lo g_{10} (10) (x + 2)

d^{3} + d^{2} + 4 d + 4 = 0

x^{5} - x - 1 = 0