solvefor x, 1/3 x+1/3 y+1/2 z=1

解答

求解

x, \frac{1}{3} x + \frac{1}{3} y + \frac{1}{2} z = 1

x = 3 - y - \frac{3}{2} z

求解步骤

\frac{1}{3} x + \frac{1}{3} y + \frac{1}{2} z = 1

将

\frac{1}{3} y

到右边

\frac{1}{3} x + \frac{1}{2} z = 1 - \frac{1}{3} y

将

\frac{1}{2} z

到右边

\frac{1}{3} x = 1 - \frac{1}{3} y - \frac{1}{2} z

在两边乘以

3

x = 3 - y - \frac{3}{2} z

\frac{f}{3} + \frac{2}{6} = \frac{2}{9} + 5 f

lo g_{10} (0.515) = 1 - 2 x

j = \frac{( 4 ^{25} \cdot 4 ^{20} ) ^{2}}{( ( 4 ^{44} ) ^{2} )}

3 x - 6 = 0.2 (5 x + 10) + 3

d = 22 + 8