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Frequently Asked Questions (FAQ)
What are the solutions to the equation x^2+5x-4=0 ?
- The solutions to the equation x^2+5x-4=0 are x=(-5+sqrt(41))/2 ,x=(-5-sqrt(41))/2
Find the zeros of x^2+5x-4=0
- The zeros of x^2+5x-4=0 are x=(-5+sqrt(41))/2 ,x=(-5-sqrt(41))/2