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Frequently Asked Questions (FAQ)
What are the solutions to the equation 4x^2+5x+7=0 ?
- The solutions to the equation 4x^2+5x+7=0 are x=-5/8+i(sqrt(87))/8 ,x=-5/8-i(sqrt(87))/8
Find the zeros of 4x^2+5x+7=0
- The zeros of 4x^2+5x+7=0 are x=-5/8+i(sqrt(87))/8 ,x=-5/8-i(sqrt(87))/8