vereinfachen (2m^3n^4p^2)^3

Lösung

vereinfachen

(2 m^{3} n^{4} p^{2})^{3}

8 m^{9} n^{12} p^{6}

Schritte zur Lösung

(2 m^{3} n^{4} p^{2})^{3}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(2 m^{3} n^{4} p^{2})^{3} = 2^{3} (m^{3})^{3} (n^{4})^{3} (p^{2})^{3}

= 2^{3} (m^{3})^{3} (n^{4})^{3} (p^{2})^{3}

2^{3} = 8

= 8 (m^{3})^{3} (n^{4})^{3} (p^{2})^{3}

Vereinfache

(m^{3})^{3} : m^{9}

= 8 m^{9} (n^{4})^{3} (p^{2})^{3}

Vereinfache

(n^{4})^{3} : n^{12}

= 8 m^{9} n^{12} (p^{2})^{3}

Vereinfache

(p^{2})^{3} : p^{6}

= 8 m^{9} n^{12} p^{6}

f a c t or 9 x^{2} + 12 x y

s im pl i f y sin^{2} (a) (sin^{2} (b))

f a c t or 75 p^{2} - 3 q^{2}

s im pl i f y (2 x + x)^{2}

s im pl i f y (3 x^{6}) - 7 + (2 x^{7}) + 6 - (9 x^{6})