What are the solutions to the equation c^2+5c=36 ?

The solutions to the equation c^2+5c=36 are c=4,c=-9

Find the zeros of c^2+5c=36

The zeros of c^2+5c=36 are c=4,c=-9

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c^{2} + 5 c = 36

c = 4, c = - 9

Solution steps

c^{2} + 5 c = 36

Move

36

to the left side

c^{2} + 5 c - 36 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 36) = 13

c_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 5 + 13}{2 \cdot 1}, c_{2} = \frac{- 5 - 13}{2 \cdot 1}

c = \frac{- 5 + 13}{2 \cdot 1} : 4

c = \frac{- 5 - 13}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

c = 4, c = - 9

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2 x^{2} - 54 = 0

x (x - 1) (x + 2) > 0

What are the solutions to the equation c^2+5c=36 ?
The solutions to the equation c^2+5c=36 are c=4,c=-9
Find the zeros of c^2+5c=36
The zeros of c^2+5c=36 are c=4,c=-9