What are the solutions to the equation 3x^2+2x=5 ?

The solutions to the equation 3x^2+2x=5 are x=1,x=-5/3

Find the zeros of 3x^2+2x=5

The zeros of 3x^2+2x=5 are x=1,x=-5/3

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3 x^{2} + 2 x = 5

x = 1, x = - \frac{5}{3}

Solution steps

3 x^{2} + 2 x = 5

Move

5

to the left side

3 x^{2} + 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 5) = 8

x_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 8}{2 \cdot 3}, x_{2} = \frac{- 2 - 8}{2 \cdot 3}

x = \frac{- 2 + 8}{2 \cdot 3} : 1

x = \frac{- 2 - 8}{2 \cdot 3} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{5}{3}

5 x^{4} - 20 x^{3} + 20 x^{2}

4 x^{3} + 32

5 x^{2} + 4 x - 12

- \frac{1}{2} x^{3} y^{2} - 7 y^{5} + x^{3} y^{2}

\frac{1}{36}

What are the solutions to the equation 3x^2+2x=5 ?
The solutions to the equation 3x^2+2x=5 are x=1,x=-5/3
Find the zeros of 3x^2+2x=5
The zeros of 3x^2+2x=5 are x=1,x=-5/3