faktorisieren tan^2(t)-16cos^2(t)

Lösung

faktorisieren

tan^{2} (t) - 16 cos^{2} (t)

(tan (t) + 4 cos (t)) (tan (t) - 4 cos (t))

Schritte zur Lösung

tan^{2} (t) - 16 cos^{2} (t)

Vereinfache

16 cos^{2} (t) : (4 cos (t))^{2}

= tan^{2} (t) - (4 cos (t))^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

tan^{2} (t) - (4 cos (t))^{2} = (tan (t) + 4 cos (t)) (tan (t) - 4 cos (t))

= (tan (t) + 4 cos (t)) (tan (t) - 4 cos (t))

s im pl i f y (\frac{x}{( x - 1 )})^{2} - 3 (\frac{x}{( x - 1 )}) - 18

s im pl i f y \frac{( 2 ^{x} ) ^{x} - ( 2 ^{2} \cdot 2 ^{x} )}{2}

j o in \frac{arctan ( a )}{b - arctan ( a - \frac{b}{a} + b )}

s im pl i f y 148231 - 26115064461 - 50 a^{0}

s im pl i f y (v) (5 x^{- 3} \cdot y \cdot z^{2})^{- 2}