What are the solutions to the equation 10x^2+9=499 ?

The solutions to the equation 10x^2+9=499 are x=7,x=-7

Find the zeros of 10x^2+9=499

The zeros of 10x^2+9=499 are x=7,x=-7

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10 x^{2} + 9 = 499

x = 7, x = - 7

Solution steps

10 x^{2} + 9 = 499

Move

9

to the right side

10 x^{2} = 490

Divide both sides by

10

x^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 49, x = - 49

49 = 7

- 49 = - 7

x = 7, x = - 7

- \frac{7}{2} \cdot 2

(7 + 7 i) (- 10 + 3 i)

3 (x + 2) + x = 4 (x - 1) + 9

\frac{3}{2} + \frac{1}{5}

∣ 2 (x - 1) + 4 ∣ \leq 6

What are the solutions to the equation 10x^2+9=499 ?
The solutions to the equation 10x^2+9=499 are x=7,x=-7
Find the zeros of 10x^2+9=499
The zeros of 10x^2+9=499 are x=7,x=-7